Define density and provide its $SI$ unit.
(N/A) Density of a substance is defined as its mass per unit volume.
The formula for density is: $D = \frac{m}{V}$
$SI$ units of density are derived as follows:
$SI$ unit of density $= \frac{\text{SI unit of mass}}{\text{SI unit of volume}} = \frac{kg}{m^{3}} = kg \ m^{-3}$
Since this unit is quite large,chemists often express density in $g \ cm^{-3}$,where mass is measured in grams and volume in $cm^{3}$.
The formula for density is: $D = \frac{m}{V}$
$SI$ units of density are derived as follows:
$SI$ unit of density $= \frac{\text{SI unit of mass}}{\text{SI unit of volume}} = \frac{kg}{m^{3}} = kg \ m^{-3}$
Since this unit is quite large,chemists often express density in $g \ cm^{-3}$,where mass is measured in grams and volume in $cm^{3}$.
Explore More
Similar Questions
Evaluate the following exponential numbers:
$(i)$ Add $8.56 \times 10^{6}$ and $10.64 \times 10^{5}$.
$(ii)$ Subtract $5.80 \times 10^{-4}$ from $3.33 \times 10^{-3}$.
$(i)$ Add $8.56 \times 10^{6}$ and $10.64 \times 10^{5}$.
$(ii)$ Subtract $5.80 \times 10^{-4}$ from $3.33 \times 10^{-3}$.
Easy
View SolutionHow many significant figures are present in the following?
$(i)$ $0.0025$
$(ii)$ $208$
$(iii)$ $5005$
$(iv)$ $126.000$
$(v)$ $500.0$
$(vi)$ $2.0034$
$(i)$ $0.0025$
$(ii)$ $208$
$(iii)$ $5005$
$(iv)$ $126.000$
$(v)$ $500.0$
$(vi)$ $2.0034$
Medium
View SolutionGiven $P = 0.0030 \ m$,$Q = 2.40 \ m$,$R = 3000 \ m$. The significant figures in $P, Q$,and $R$ are respectively:
Medium
View Solution$1 \, \mu g = ........ \, mg$
Easy
View Solution$A$ picometre is written as
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo